A subscriber base evolves with dominant eigenvalue $\lambda = 1.2$ per year, starting aligned with the eigenvector at 100k subscribers. Set the slider to the size after 3 years (thousands).

Estimate on a scale from 0k (0) to 300k (300).

Hints

Each year multiplies by 1.2.
$100 \cdot 1.2^3$ .

Show the answer

172.8 (answers within ±8 count)

Why

$100 \cdot 1.2^3 = 172.8$ k. On an eigenvector, matrix dynamics collapse to plain compounding, that reduction of a many-variable system to one growth rate is the entire practical value of eigenvalues.

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Practise Eigenvalues and Eigenvectors

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A subscriber base evolves with dominant eigenvalue λ=1.2\lambda = 1.2λ=1.2 per year, starting aligned with the eigenvector at 100k subscribers. Set the slider to the size after 3 years (thousands).

Practise Eigenvalues and Eigenvectors

More questions on Eigenvalues and Eigenvectors

A subscriber base evolves with dominant eigenvalue $\lambda = 1.2$ per year, starting aligned with the eigenvector at 100k subscribers. Set the slider to the size after 3 years (thousands).