Practice question · Match the pairs
Match each salt formula type to its relation between solubility product and molar solubility.
- AB, such as silver chloride
- , such as calcium fluoride
- , such as silver phosphate
- Any pure solid phase
- Omitted from the expression entirely
Hints
- Raise each ion concentration to its own coefficient and multiply.
- For A3B the first ion is at 3s and is cubed, giving 27 s to the fourth.
Show the answer
- AB, such as silver chloride →
- , such as calcium fluoride →
- , such as silver phosphate →
- Any pure solid phase → Omitted from the expression entirely
Why
Each ion appears at its stoichiometric multiple of and raised to its coefficient, which is where the numerical prefactors 4 and 27 come from. Pure solids never appear, since their concentration cannot vary.
Practise Solubility Equilibria
The app has 4 more questions on this lesson, and keeps your place in the course. Chemistry I is free to start.
More questions on Solubility Equilibria
- Complete the explanation of why two solubility products cannot be compared directly.
- A solution chemist claims that the solubility product constant reflects the equilibrium position of…
- A salt of formula AB2 has a molar solubility of 1.0 × 10⁻² M. Compute its solubility product, in units of…
- Sort each condition by what happens to a sparingly soluble salt in the solution.
- Adding sodium chloride to a saturated solution of silver chloride increases the amount of silver chloride…
- A precipitating reagent is added slowly to a solution containing two metal ions with very different…
- A 1:1 salt has Ksp = 9.0 × 10⁻¹². Compute its molar solubility in pure water, in units of 10⁻⁶ M.