Practice question · Multiple choice
Gram-Schmidt takes a perfectly good basis and replaces it with an orthonormal one. Why is that worth the computation, when the original basis already gives every vector unique coordinates?
Hints
- Given a basis and a vector, how do you actually FIND the coordinates in each case?
- Ask what the inner product with a basis vector tells you when the others are perpendicular to it.
Show the answer
A. Because each coordinate becomes a single inner product.
Why
Both bases give unique coordinates and differ entirely in what it costs to get them: a general basis means solving a linear system for every vector, where an orthonormal one gives cᵢ = ⟨w, eᵢ⟩ because every other term is killed. That independence is what makes the idea far-reaching. Fourier series are this construction in a space of functions.
Practise Inner Product Spaces and Orthogonality
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More questions on Inner Product Spaces and Orthogonality
- Select every TRUE statement about inner products and orthogonality.
- Order the steps of the Gram-Schmidt process applied to a basis v1, v2, v3.
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