Practice question · Put in order
Order the steps of Euclid's proof that there are infinitely many primes.
- So no pi divides N, yet N has some prime factor
- That prime factor is missing from the list, contradicting the assumption
- Observe that N leaves remainder 1 on division by each pi
- Form N by multiplying all of them together and adding 1
- Assume for contradiction that the primes are just p1, p2, ..., pk
Hints
- A proof by contradiction opens by assuming the opposite of what you want.
- The contradiction is not that N is prime, it is that N needs a prime that was not listed.
Show the answer
- Assume for contradiction that the primes are just p1, p2, ..., pk
- Form N by multiplying all of them together and adding 1
- Observe that N leaves remainder 1 on division by each pi
- So no pi divides N, yet N has some prime factor
- That prime factor is missing from the list, contradicting the assumption
Why
Assume finiteness, build a number that dodges every listed prime, then note it still has SOME prime factor, which must therefore be new. The subtle point is that N need not itself be prime, it only needs a prime factor outside the list.
Practise Primes and the Fundamental Theorem of Arithmetic
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