Practice question · Numerical answer
A print needs to be one third of a stop darker overall. Its base exposure is 15 seconds. What is the new base exposure, in seconds, to the nearest whole second?
Hints
- A third of a stop multiplies the time by about 1.26.
- 15 times 1.26.
Show the answer
19 (answers within ±0.6 count)
Why
19 seconds. 15 multiplied by 1.26 is 18.9. Working in thirds of a stop rather than in arbitrary seconds is what keeps the adjustment meaningful: the same instruction applied to a 40-second base gives 50 seconds, and the visual change is identical.
Practise Dodging, Burning and the Expressive Print
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