Physics I / Conservation of Energy
Practice question · Estimate

A pendulum bob is pulled up until it is 20 cm above its lowest point, then released. Estimate its speed at the bottom of the swing.

Estimate on a scale from 0 m/s (0) to 5 m/s (5).

Hints
  1. All the height energy becomes motion energy: mgh=12mv2mgh = \frac{1}{2}mv^{2}, the mass cancels.
  2. v=2gh=2×9.8×0.2v = \sqrt{2gh} = \sqrt{2 \times 9.8 \times 0.2}.
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2 (answers within ±0.3 count)

Why

v=2×9.8×0.21.98v = \sqrt{2 \times 9.8 \times 0.2} \approx 1.98 m/s. Notice the string tension does no work, it always pulls perpendicular to the motion, so only gravity matters.

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