Physics I / Differential models in one variable
Practice question · Match the pairs

Match each differential equation to the story it tells.

  • y=ky,  k>0y' = ky,\; k > 0
  • y=ky,  k>0y' = -ky,\; k > 0
  • y=k(Ay)y' = k(A - y)
  • y=ky(1y/M)y' = ky(1 - y/M)
  • Unchecked growth (compound interest)
  • Growth that saturates (logistic population)
  • Decay toward zero (radioactivity)
  • Approach to a ceiling (coffee cooling)
Hints
  1. Ask of each equation: where is yy' zero? That is where the system can rest.
  2. The logistic starts exponential (small yy) and strangles itself as yMy \to M.
Show the answer
  • y=ky,  k>0y' = ky,\; k > 0 Unchecked growth (compound interest)
  • y=ky,  k>0y' = -ky,\; k > 0 Decay toward zero (radioactivity)
  • y=k(Ay)y' = k(A - y) Approach to a ceiling (coffee cooling)
  • y=ky(1y/M)y' = ky(1 - y/M) Growth that saturates (logistic population)
Why

Four rate laws cover a remarkable share of science. Reading equilibria (y=0y'=0) and signs of yy' gives you the full qualitative story before any solving, often that is all you need.

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