Physics I / Graphs, approximation, and numerical sense
Practice question · Multiple choice

Newton’s method races to a root when it works, but pick the starting point badly and it fails. Which situation breaks it?

Hints
  1. Each step is xn+1=xnf(xn)/f(xn)x_{n+1} = x_n - f(x_n)/f'(x_n). Look for the danger in that fraction.
  2. Dividing by a near-zero slope launches the next guess toward the horizon.
Show the answer

C. Starting where f(x0)0f'(x_0) \approx 0

Why

A flat tangent barely tilts toward zero, so its root-crossing lies absurdly far away: division by f0f' \approx 0 catapults the iteration. Away from flat spots, though, the method roughly doubles the correct digits every step: flawed and brilliant at once.

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