Physics I / Kirchhoff's Laws and Circuit Analysis
Practice question · Multiple choice

Three identical bulbs: A is in series with the battery; the pair B and C are in parallel with each other after A. If bulb C burns out (breaks the branch), what happens to bulb A?

Hints
  1. Removing C leaves B alone where the parallel pair used to be. Does the branch resistance rise or fall?
  2. A parallel pair of equal resistors has half the resistance of one alone. Total series resistance therefore increases when C dies.
Show the answer

A. A gets dimmer: total resistance rose

Why

Losing C turns the parallel pair (R/2R/2) into a single bulb (RR), raising the loop resistance from 1.5R1.5R to 2R2R. The battery pushes less current, so A dims, while B, now receiving the full branch current, actually brightens.

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