You must compute the work $\int_C \vec{F}\cdot d\vec{r}$ along a complicated spiral path, and you notice $\vec{F} = \nabla f$ for some potential $f$. What is the fastest correct move?

C. Evaluate $f$ at the endpoints: work $= f(\text{end}) - f(\text{start})$

Conservative fields make the path irrelevant: $\int_C \nabla f \cdot d\vec{r} = f(B) - f(A)$ exactly, spiral or not. This is why potential energy exists, and why "work done against gravity" depends on height gained, never on the route taken.