Physics I / Optimization: Critical Points and Lagrange Multipliers
Practice question · Match the pairs

Match each second derivative test outcome to the classification.

  • D > 0, fxxf_{xx} > 0
  • D > 0, fxxf_{xx} < 0
  • D < 0
  • D=0D = 0
  • Test inconclusive
  • Local maximum
  • Local minimum
  • Saddle point
Hints
  1. The discriminant's sign comes first, then the sign of one second derivative.
  2. A negative discriminant settles the case on its own.
Show the answer
  • D > 0, fxxf_{xx} > 0 Local minimum
  • D > 0, fxxf_{xx} < 0 Local maximum
  • D < 0 Saddle point
  • D=0D = 0 Test inconclusive
Why

The discriminant D=fxxfD = f_{xx}fᵧᵧ − (fxf_{x}ᵧ)² determines the critical point type.

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