Double slit: $d = 0.1 mm$ , $\lambda$ = 500 nm. What is the angle (in degrees) for the first bright fringe ( $m=1)$ ? Set the slider to your answer.

Estimate on a scale from 0 to 0.8.

Hints

Show the answer

0.29 (answers within ±0.01 count)

Why

sin $\theta$ = mλ/ $d = 500\times10$ ⁻⁹/10⁻⁴ = 0.005 → $\theta$ = $arcsin(0.005)$ $\approx 0.29$ °.

Practise Wave Optics: Interference and Diffraction

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