A closed surface encloses a net charge of +3.54 × 10⁻¹¹ C. Compute the electric flux through it, in N m²/C, using ε0 = 8.854 × 10⁻¹² F/m. Give the answer to one decimal place.

Practice question · Numerical answer

A closed surface encloses a net charge of $+3.54 \times 10^{-11}$ C. Compute the electric flux through it, in N m $^2$ /C, using $\varepsilon_0 = 8.854 \times 10^{-12}$ F/m. Give the answer to one decimal place.

Hints

Flux through a closed surface is the enclosed charge divided by the permittivity of free space.
Compute 3.54e-11 / 8.854e-12.

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4 (answers within ±0.15 count)

Why

Gauss’s law gives $\Phi = Q_{enc}/\varepsilon_0 = 3.54 \times 10^{-11}/8.854 \times 10^{-12} = 4.0$ N m $^2$ /C. The shape of the surface is irrelevant, only the charge inside it matters.

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A closed surface encloses a net charge of +3.54×10−11+3.54 \times 10^{-11}+3.54×10−11 C. Compute the electric flux through it, in N m2^22/C, using ε0=8.854×10−12\varepsilon_0 = 8.854 \times 10^{-12}ε0​=8.854×10−12 F/m. Give the answer to one decimal place.

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A closed surface encloses a net charge of $+3.54 \times 10^{-11}$ C. Compute the electric flux through it, in N m $^2$ /C, using $\varepsilon_0 = 8.854 \times 10^{-12}$ F/m. Give the answer to one decimal place.