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Integral Calculus

Integration by Parts

Mathematics I 232 words Free to read

Reversing the Product Rule

Integration by parts reverses the product rule to handle integrals of products that substitution cannot touch. The formula is: udv=uvvdu\int u\, dv = uv - \int v\, du Here, uu is differentiated and dvdv is integrated, trading your original integral for a hopefully simpler one.

The art is choosing uu and dvdv wisely. Use the mnemonic LIATE to order your choices for uu:

PriorityCategoryExample
1Logarithmicln(x)\ln(x)
2Inverse trigarctan(x)\arctan(x)
3Algebraicx2x^2
4Trigonometricsin(x)\sin(x)
5Exponentialexe^x

Pick uu as the type appearing earliest in LIATE, and let dvdv contain the rest.

A rectangle split in two by a rising curve --- the identity as area

Worked Example & Pitfalls

For xexdx\int x e^x\, dx, choose u=xu = x (algebraic, giving du=dxdu = dx) and dv=exdxdv = e^x\, dx (giving v=exv = e^x). Applying the formula: xexdx=xexexdx=xexex+C\int x e^x\, dx = x e^x - \int e^x\, dx = x e^x - e^x + C Sometimes parts must be applied twice, like for x2exdx\int x^2 e^x\, dx.

Common pitfall: choosing uu and dvdv badly, making vdu\int v\, du harder than the original. Always pick uu to get simpler when differentiated.

Recall the core split:

Practise this lesson

The explanation above is free to read. The graded practice for this lesson lives in the Tryals app.

11practice questions
2interactive scenes

Integral Calculus