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Differential Calculus

Related Rates and Implicit Differentiation

Mathematics I 187 words Free to read

Implicit Differentiation

Not every curve is written as y=f(x)y = f(x). An implicit relation like x2+y2=25x^2 + y^2 = 25 defines yy through xx without solving for it explicitly.

Implicit differentiation finds dydx\frac{dy}{dx} by differentiating both sides with respect to xx. Treat yy as a function of xx and apply the chain rule to every yy-term.

RelationActionResult
y2y^2ddx\frac{d}{dx}2ydydx2y\frac{dy}{dx}
x2+y2=25x^2 + y^2 = 25ddx\frac{d}{dx}2x+2ydydx=02x + 2y\frac{dy}{dx} = 0

Solving yields dydx=xy\frac{dy}{dx} = -\frac{x}{y}. This handles tangled curves that resist explicit isolation.

A tangent measured on a curve that was never solved for y

Related Rates

When quantities link up and change over time tt, their rates link up too. Differentiate with respect to tt, bringing in a ddt\frac{d}{dt} factor for every changing variable.

Method: Write equation \rightarrow Differentiate wrt tt \rightarrow Substitute and solve.

For a sphere (V=43πr3V = \frac{4}{3}\pi r^3), differentiating gives dVdt=4πr2drdt\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}.

Common pitfall: Forgetting the chain rule factor (like dydx\frac{dy}{dx} or drdt\frac{dr}{dt}) on dependent variables. Treating y2y^2 as just 2y2y is the classic fatal error.

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Differential Calculus