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Multivariable Calculus

Double Integrals

A double integral computes the volume under z = f(x,y) over R: Iterated integrals — Evaluate one variable at a time: Fubini's theorem — If f is continuo…

Physics I 195 words Free to read

A double integral computes the volume under z=f(x,y)z = f(x,y) over RR:

Rf(x,y)dA\iint_R f(x,y)\,dA

Iterated integrals — Evaluate one variable at a time:

RfdA=abg1(x)g2(x)fdydx\iint_R f\,dA = \int_a^b\int_{g_1(x)}^{g_2(x)} f\,dy\,dx

Fubini's theorem — If ff is continuous on RR, integrate in either order.

Applications

Sketch RR and choose the integration order that gives simpler limits.

Key insight: The key skill is setting up the correct limits of integration.
Common pitfall: In iterated integrals the inner limits may depend on the outer variable, never the reverse. Writing 0y\int_0^{y}\ldots as the outer integral is the classic setup error — sketch the region first.
Placeholder: Double Integrals

Geometric Meaning of the Double Integral

The double integral Rf(x,y)dA\iint_R f(x,y)\,dA computes the signed volume between the surface z=f(x,y)z = f(x,y) and the xyxy-plane over region RR.

To evaluate, integrate iteratively:

RfdA=abg1(x)g2(x)fdydx\iint_R f\,dA = \int_a^b \int_{g_1(x)}^{g_2(x)} f\,dy\,dx

The base region RR determines the limits. Choosing the right order can greatly simplify the calculation.

Double integrals generalize single-variable integrals to two variables — the key is correct limits.
Double Integral in 3D

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The explanation above is free to read. The graded practice for this lesson lives in the Tryals app.

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Multivariable Calculus