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Calculus of a Single Variable

Integrals as accumulation

Physics I 129 words Free to read

The definite integral measures the signed area under a curve:

abf(x)dx  =  limni=1nf(xi)Δx\int_{a}^{b} f(x)\,dx \;=\; \lim_{n\to\infty}\sum_{i=1}^{n} f(x_{i}^{*})\,\Delta x

Riemann sums — Partition [a,b][a,b] into nn sub-intervals of width Δx=ban\Delta x = \tfrac{b-a}{n}, pick a sample point xix_i^* in each, and sum.

Properties

ab[αf+βg]dx=αabfdx+βabgdx\int_a^b [\alpha f + \beta g]\,dx = \alpha\int_a^b f\,dx + \beta\int_a^b g\,dx

acfdx=abfdx+bcfdx\int_a^c f\,dx = \int_a^b f\,dx + \int_b^c f\,dx

favg=1baabf(x)dxf_{\text{avg}} = \frac{1}{b-a}\int_a^b f(x)\,dx

Basic antiderivatives

Physics link: Work done by a variable force is W=abF(x)dxW=\int_{a}^{b}F(x)\,dx.
Common pitfall: A definite integral is a signed number, not an area: regions below the axis count negative. "Total area enclosed" questions require splitting at the zero crossings first.
Calculus: Integrals as accumulation

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Calculus of a Single Variable