Business I / First-Order Differential Equations
Practice question · Multiple choice

Half-life from a decay rate kk is computed as ln2/k\ln 2 / |k| rather than 2/k2/k. Why does a logarithm appear?

Hints
  1. Write ekt=1/2e^{-kt} = 1/2 and solve for tt.
  2. What operation undoes an exponential?
Show the answer

A. Because halving is reached after a fixed multiple of 1/k1/k

Why

The logarithm is what inverts the exponential. It is also why half-life is constant: the time to halve does not depend on where you start, which is peculiar to exponential decay.

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