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Mathematics II

First-Order Differential Equations

Business I 267 words Free to read

First-Order ODEs & Methods

A differential equation relates a function to its derivatives, describing how something changes. First-order ODEs involve only the first derivative: dydt=f(t,y)\frac{dy}{dt} = f(t, y).

Separable equations occur when f(t,y)=g(t)h(y)f(t,y) = g(t) h(y). Separate variables and integrate:

dyh(y)=g(t)dt\int \frac{dy}{h(y)} = \int g(t)\, dt

Linear first-order ODEs follow dydt+p(t)y=q(t)\frac{dy}{dt} + p(t) y = q(t). Solve using the integrating factor μ(t)=ep(t)dt\mu(t) = e^{\int p(t)\, dt}:

y(t)=1μ(t)μ(t)q(t)dty(t) = \frac{1}{\mu(t)} \int \mu(t) q(t)\, dt

TypeFormMethod
Separabledy/dt=g(t)h(y)dy/dt = g(t)h(y)Separate and integrate
Lineardy/dt+p(t)y=q(t)dy/dt + p(t)y = q(t)Integrating factor epdte^{\int p\,dt}
Exponentialdy/dt=kydy/dt = kyDirect: y0ekty_0 e^{kt}
Common pitfall: Dividing by h(y)h(y) assumes h(y)0h(y) \neq 0. Always check constant solutions where h(y)=0h(y) = 0 separately.
Two methods, each performed as an actual rearrangement rather than

Economic Models & Stability

The exponential growth/decay model dydt=ky\frac{dy}{dt} = ky yields y(t)=y0ekty(t) = y_0 e^{kt}. If k>0k > 0, it is growth; if k<0k < 0, it is decay.

Key economic applications include:

The steady state occurs where dy/dt=0dy/dt = 0. For y˙=f(y)\dot{y} = f(y) near equilibrium yy^*, stability depends on the derivative sign.

DerivativeStabilityBehavior
f(y)<0f'(y^*) < 0StableDeviations shrink
f(y)>0f'(y^*) > 0UnstableDeviations grow

Practise this lesson

The explanation above is free to read. The graded practice for this lesson lives in the Tryals app.

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Mathematics II