Chemistry I / Gases, Kinetic Theory and Intermolecular Forces
Practice question · Numerical answer

How many moles of an ideal gas occupy 22.4 L at 273 K and 1.00 atm? Use R=0.0821R = 0.0821 L atm mol1^{-1} K1^{-1} and give the answer to one decimal place.

Hints
  1. Rearrange the ideal gas equation to make n the subject.
  2. Compute (1.00 x 22.4)/(0.0821 x 273).
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1 (answers within ±0.05 count)

Why

n=PV/RT=(1.00×22.4)/(0.0821×273)=22.4/22.41=1.0n = PV/RT = (1.00 \times 22.4)/(0.0821 \times 273) = 22.4/22.41 = 1.0 mol. This is the molar volume at STP, and it is the same for every ideal gas.

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