Chemistry I / Reaction Kinetics
Practice question · Multiple choice

Doubling the concentration of reactant A leaves the reaction rate unchanged. Which order with respect to A best explains this?

Hints
  1. Express the rate ratio as the concentration ratio raised to the order.
  2. Anything to the power zero is 1, so the rate does not respond.
Show the answer

D. Zero order

Why

Rate [A]m\propto [A]^m, so doubling [A][A] multiplies the rate by 2m2^m. An unchanged rate means 2m=12^m = 1, giving m=0m = 0, zero order, typical of surface-saturated catalytic reactions.

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