Chemistry I / Reaction Kinetics
Practice question · Numerical answer

When [A][A] is doubled, the rate of a reaction increases by a factor of 4. What is the order with respect to A?

Hints
  1. Write the factor as 2 raised to the order.
  2. Solve 2^m = 4.
Show the answer

2

Why

The rate multiplies by 2m2^m, so 2m=42^m = 4 gives m=2m = 2, second order in A. Its half-life would then depend on the starting concentration, unlike a first-order reaction.

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