Practice question · Multiple choice
The cyclic integral of actual heat exchange over temperature is non-positive, whereas entropy change is defined strictly through reversible heat. What does this distinction mean for evaluating system transformations?
Hints
- What does the inequality imply when you complete an irreversible path with a reversible return?
- Can a state variable ever depend on the specific route taken between endpoints?
Show the answer
B. Actual transferred heat is only a lower bound on the true change in entropy
Why
Because the Clausius inequality bounds the cyclic integral below zero, the real irreversible heat transferred along a path yields less than the genuine state difference ΔS. Entropy is never destroyed, nor does a state function retain any memory of past heat paths.
Practise The Second Law and Entropy
The app has 5 more questions on this lesson, and keeps your place in the course. Physics II is free to start.
More questions on The Second Law and Entropy
- Why are the Kelvin-Planck and Clausius statements of the second law equivalent?
- To find the entropy change of an irreversible process, you may integrate the actual heat divided by…
- An isolated system undergoes a process in which one part gains 12 J/K of entropy and another loses 7 J/K.…
- Which statements about entropy are correct?
- The thermodynamic identity dU = T dS - P dV holds even for irreversible processes.