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Principles of Electromagnetism and Optics

Current, Resistance, and DC Circuits

Physics I 261 words Free to read

A copper wire carries no more charge when current flows than when it does not — the electrons were always there, drifting slower than honey (about 0.1 mm/s). What makes a bulb light instantly is that the push propagates near light speed, like water pressure through a full hose.

Electric current is the rate of charge flow:

I=dQdt,unit: ampere (A)I = \frac{dQ}{dt}, \qquad \text{unit: ampere (A)}

Ohm's law relates voltage, current, and resistance:

V = IR

ResistivityR=ρL/AR = \rho L/A, where ρ\rho is the material's resistivity, LL is length, and AA is cross-sectional area.

Power dissipated in a resistor:

P=IV=I2R=V2RP = IV = I^2R = \frac{V^2}{R}

Resistor combinations

ConfigurationEquivalent RR
SeriesReq=R1+R2+sR_{\text{eq}} = R_1 + R_2 + \cdot s
Parallel1Req=1R1+1R2+s\dfrac{1}{R_{\text{eq}}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \cdot s

Joule heating — Energy dissipated as heat: E=Pt=I2RtE = Pt = I^{2}Rt. This is why transmission lines use high voltage and low current.

V = 12.0   # volts (battery)
R1, R2 = 100, 200  # ohms in series
I = V / (R1 + R2)
P = I**2 * (R1 + R2)
print(f"Current = {I:.4f} A, Power = {P:.4f} W")

Key insight: Resistors in series share the same current; resistors in parallel share the same voltage. This determines which combination rule to use.
Common pitfall: Current is not "used up" around a circuit. The same current that leaves the battery returns to it; what gets spent is energy per charge (voltage). Series bulbs share voltage, not diminishing current.
Placeholder: Current, Resistance, and DC Circuits

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Principles of Electromagnetism and Optics