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Differential Equations and Vector Calculus

Second-Order Linear ODEs

Physics I 258 words Free to read

A Second-Order Linear ODE takes the form ay+by+cy=f(x)ay'' + by' + cy = f(x). When the homogeneous case applies (f=0f=0), we test y=erxy = e^{rx} to find the characteristic equation ar2+br+c=0ar^2 + br + c = 0.

The general solution depends on the discriminant Δ=b24ac\Delta = b^2 - 4ac:

CaseRootsGeneral Solution (yy)
Δ>0\Delta > 0r1r2r_1 \neq r_2 (real)C1er1x+C2er2xC_1 e^{r_1 x} + C_2 e^{r_2 x}
Δ=0\Delta = 0rr (repeated)(C1+C2x)erx(C_1 + C_2 x)e^{rx}
Δ<0\Delta < 0α±βi\alpha \pm \beta i (complex)eαx(C1cosβx+C2sinβx)e^{\alpha x}(C_1\cos\beta x + C_2\sin\beta x)

For non-homogeneous equations, the complete solution is y=yh+ypy = y_h + y_p using undetermined coefficients or variation of parameters.

Placeholder: Second-Order Linear ODEs

Damped Oscillators & Pitfalls

Common pitfall: Stopping at yhy_h misses the steady-state (ypy_p), while stopping at ypy_p drops the transient. You must include both.

Adding damping to a spring gives mx¨+bx˙+kx=0m\ddot{x} + b\dot{x} + kx = 0. Behaviour is governed by the damping ratio ζ=b2mk\zeta = \frac{b}{2\sqrt{mk}}:

Damping TypeRatio ConditionPhysical Behaviour
Underdampedζ<1\zeta < 1Oscillations with exponential decay
Critically dampedζ=1\zeta = 1Fastest return to zero without oscillation
Overdampedζ>1\zeta > 1Slow, sluggish exponential return

Physics link: Critical damping (ζ=1\zeta = 1) is used in door closers and shock absorbers to achieve equilibrium in minimum time.

Damped Oscillator

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Differential Equations and Vector Calculus