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Differential Equations and Vector Calculus

Surface Integrals

Physics I 158 words Free to read

A surface integral extends integration from curves to two-dimensional surfaces in R3\mathbb{R}^{3}.

Parametric surface — A surface SS parametrised by (u,v)(u,v):

r(u,v)=x(u,v)i^+y(u,v)j^+z(u,v)k^\vec{r}(u,v) = x(u,v)\,\hat{i} + y(u,v)\,\hat{j} + z(u,v)\,\hat{k}

Normal vector and area element

dS=(ru×rv)dudvd\vec{S} = \left(\frac{\partial\vec{r}}{\partial u}\times\frac{\partial\vec{r}}{\partial v}\right)du\,dv

Scalar surface integral

SfdS=Df(r(u,v))ru×rvdudv\iint_S f\,dS = \iint_D f(\vec{r}(u,v))\,\left\|\frac{\partial\vec{r}}{\partial u}\times\frac{\partial\vec{r}}{\partial v}\right\|\,du\,dv

Flux integral — The flow of F\vec{F} through SS:

Φ=SFdS=SFn^dS\Phi = \iint_S \vec{F}\cdot d\vec{S} = \iint_S \vec{F}\cdot\hat{n}\,dS

Special case — If SS is a graph z=g(x,y)z = g(x,y):

dS=(gxi^gyj^+k^)dxdyd\vec{S} = (-g_x\,\hat{i} - g_y\,\hat{j} + \hat{k})\,dx\,dy

Orientation matters: the choice of n^\hat{n} (outward vs. inward for a closed surface) determines the sign of the flux.

Physics link: Electric flux through a closed surface gives the enclosed charge: ΦE=SEdS=Qenc/ε0\Phi_E = \oiint_S \vec{E}\cdot d\vec{S} = Q_{\text{enc}}/\varepsilon_0 (Gauss's law in integral form).
Common pitfall: Flux integrals are orientation-sensitive: flipping the surface normal flips the sign. Fix the normal’s direction (outward? upward?) before integrating, or the "right" magnitude arrives with the wrong sign.

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Differential Equations and Vector Calculus