Practice question · Multiple choice
Diluting an equimolar buffer ten-fold leaves its pH virtually unchanged, yet it compromises its protective function. What accounts for this apparent contradiction?
Hints
- Which variable in the Henderson-Hasselbalch equation depends on absolute quantities rather than relative proportions?
- What determines the total quantity of strong acid or base a solution can neutralise before its pH breaks?
Show the answer
C. The ratio is fixed, but the total moles of buffer pair decrease
Why
Dilution scales both components equally, preserving the logarithmic ratio that dictates pH, but reduces the absolute reservoir of ions available to neutralise incoming stress. A system's set point is distinct from its operational endurance.
Practise Buffers, Hydrolysis and Titration
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More questions on Buffers, Hydrolysis and Titration
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