Complete the statement with the correct term.

The inflection point of $f(x) = x^{3} - 3x$ is found by solving f''(x) = 0.

$f''(x) = 6x$. Setting $6x = 0$ gives $x = 0$. Concavity changes sign there: $f'' < 0$ for $x < 0$, $f'' > 0$ for $x > 0$.