Physics I / Integrated single-variable calculus problems
Practice question · Estimate

Find the area between y=xy = x and y=x2y = x^{2} on [0, 1]. Set the slider to your answer.

Estimate on a scale from 0 to 0.5.

Hints
  1. Integrate the difference of the two functions across the interval.
  2. On this interval one curve stays above the other throughout.
Show the answer

0.1667 (answers within ±0.005 count)

Why

01(xx2)dx\int_{0}^{1} (x - x^{2}) dx = [x2/2x^{2}/2x3/3x^{3}/3]₀¹ = 1/2 − 1/3 = 1/6 0.1667\approx 0.1667.

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