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Mathematics II

Eigenvalues and Eigenvectors

Given a square matrix A, an eigenvector v is a non-zero vector that A merely scales — it doesn't change direction: The scalar is the eigenvalue — the fa…

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The Directions That Don't Rotate

Given a square matrix AA, an eigenvector v\mathbf{v} is a non-zero vector that AA merely scales — it doesn't change direction:

Av=λvA\mathbf{v} = \lambda \mathbf{v}

The scalar λ\lambda is the eigenvalue — the factor by which AA stretches (or compresses, or flips) the eigenvector.

Finding eigenvalues: rearrange as (AλI)v=0(A - \lambda I)\mathbf{v} = \mathbf{0}. For a non-trivial solution, the matrix (AλI)(A - \lambda I) must be singular:

det(AλI)=0\det(A - \lambda I) = 0

This is the characteristic equation — a polynomial in λ\lambda whose roots are the eigenvalues.

For a 2×22 \times 2 matrix A=(abcd)A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}:

det(AλI)=λ2(a+d)λ+(adbc)=0\det(A - \lambda I) = \lambda^2 - (a+d)\lambda + (ad - bc) = 0

The sum of eigenvalues equals the trace (a+da + d); the product equals the determinant (adbcad - bc). These shortcuts are useful for quick checks.

Economic applications:

Eigenvalues answer the most fundamental question about a linear system: does it grow, shrink, or stay the same — and in which directions?

The 2×22 \times 2 shortcut

QuantityFormulaCheck
Characteristic equationλ2tr(A)λ+detA=0\lambda^2 - tr(A)\lambda + \det A = 0
Sum of eigenvaluesλ1+λ2=tr(A)\lambda_1 + \lambda_2 = tr(A)Fast error catch
Product of eigenvaluesλ1λ2=detA\lambda_1 \lambda_2 = \det AFast error catch
Tip: For any 2×22 \times 2 matrix, skip the determinant expansion: write λ2(trace)λ+det=0\lambda^2 - (\text{trace})\lambda + \det = 0 directly, then verify roots against trace and determinant. Twenty seconds, self-checking.

Practise this lesson

The explanation above is free to read. The graded practice for this lesson lives in the Tryals app.

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Mathematics II