Courses / Business I
Mathematics II

Unconstrained Multivariable Extrema

Business I 237 words Free to read

Finding Peaks and Pits

To find unconstrained extrema of f(x,y)f(x,y), begin with First-Order Conditions: set fx=0f_x = 0 and fy=0f_y = 0. Their simultaneous solutions are critical points—our sole candidates for local extrema.

Next, use Second-Order Conditions via the Hessian matrix to classify each point:

H=(fxxfxy fyxfyy)H = \begin{pmatrix} f_{xx} & f_{xy} \ f_{yx} & f_{yy} \end{pmatrix}

Compute the determinant D=fxxfyy(fxy)2D = f_{xx} f_{yy} - (f_{xy})^2 to reveal the local curvature.

Common pitfall: Never check fxx<0f_{xx} < 0 and fyy<0f_{yy} < 0 separately. A large cross-term fxyf_{xy} can still yield a saddle point. Only the determinant test captures full surface interaction.

The Hessian Verdicts

The determinant DD and fxxf_{xx} classify every critical point:

DD Valuefxxf_{xx} ValueVerdictGeometric Shape
D>0D > 0<0< 0Local maximumCurves down everywhere
D>0D > 0>0> 0Local minimumCurves up everywhere
D<0D < 0AnySaddle pointMountain pass
D=0D = 0AnyInconclusiveNeeds higher analysis

Economic application: A firm choosing output qq and advertising aa to maximise profit π(q,a)\pi(q,a) relies on FOCs for candidates and the Hessian to confirm a local maximum. If the Hessian yields a saddle point, the firm is at a pass where altering mix improves profit.

The verdict is a location, not a picture of a hill

Practise this lesson

The explanation above is free to read. The graded practice for this lesson lives in the Tryals app.

13practice questions
2interactive scenes

Mathematics II